🐍 Python Pattern Challenge — Day 24

Pattern printing is a simple and effective way to improve your Python loops, repetition, and logical thinking. For Day 24, let's move from numbers to alphabets and create a simple alphabet pattern.

🎯 Today's Challenge

Write a Python program to print exactly this pattern:

A
A B
A B C
A B C D
A B C D E
A B C D E F

Can you create it with the cleanest Python code? 🏆

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Solution 1 — Using Nested for Loops

for i in range(1, 7):
    for j in range(i):
        print(chr(65 + j), end=" ")
    print()

How it works

The outer loop controls the number of rows:

for i in range(1, 7):

The inner loop controls how many letters appear in each row:

for j in range(i):

The expression:

chr(65 + j)

converts numbers into uppercase alphabets.

For example:

65 → A

66 → B

67 → C 

68 → D 

69 → E

70 → F

So each row contains one additional letter.

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Solution 2 — Using a String

letters = "ABCDEF"

for i in range(1, 7):
    print(" ".join(letters[:i]))

Output

A 

A B

A B C 

A B C D 

A B C D E 

A B C D E F

Here, slicing selects the required number of letters from the string.

For example:

letters[:4]

gives:

ABCD

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Solution 3 — Using a Function

def alphabet_pattern(n):

    for i in range(1, n + 1):
        for j in range(i):
            print(chr(65 + j), end=" ")
        print()


alphabet_pattern(6)

Using a function makes the pattern reusable.

Try:

alphabet_pattern(10)

to create a larger pattern.

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⚡ Short & Clean Code

for i in range(1, 7):
    print(*"ABCDEF"[:i])

🔥 Just two lines are enough to generate the complete pattern.

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🚀 Challenge Yourself

Can you modify this pattern:

• Continue the pattern from A to Z?
• Print the alphabets in reverse order?
• Use lowercase letters?
• Create the same pattern using a while loop?
• Make every row start with a different alphabet?
• Create a pattern using numbers and alphabets together?

Drop your solution below! 👇

24 Days. 24 Patterns. Stronger Python Logic. 🐍🔥

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