🐍 Python Pattern Challenge — Day 23

Pattern printing is a simple and effective way to improve your Python loops, repetition, and logical thinking. For Day 23, let's practice a clean number pattern where each new row contains one more number than the previous row.

🎯 Today's Challenge

Write a Python program to print exactly this pattern:

Best and cleanest code will be rewarded! 🏆

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Solution 1 — Using Nested for Loops

for i in range(1, 7):
    for j in range(1, i + 1):
        print(j, end=" ")
    print()

How it works

The outer loop controls the rows:

for i in range(1, 7):

So the loop runs 6 times.

The inner loop controls the numbers printed in each row:

for j in range(1, i + 1):

For the first row, only 1 is printed.

For the second row:

1 2

For the third row:

1 2 3

The number of elements increases by one with every new row.

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Solution 2 — Using range()

We can make the code even cleaner:

for i in range(1, 7):
    print(*range(1, i + 1))

Output

1

1 2 

1 2 3

1 2 3 4 

1 2 3 4 5

1 2 3 4 5 6

Here, * unpacks the values returned by range() before printing them.

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Solution 3 — Using a Function

def number_pattern(n):
    for i in range(1, n + 1):
        print(*range(1, i + 1))


number_pattern(6)

The function makes the pattern reusable.

For example:

number_pattern(10)

will generate the pattern up to 1 2 3 4 5 6 7 8 9 10.

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⚡ Short & Clean Code

for i in range(1, 7):
    print(*range(1, i + 1))

🔥 Just two lines are enough to create the complete Day 23 pattern.

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🚀 Challenge Yourself

Can you modify this pattern:

• Make the pattern go up to 10?
• Print the numbers in reverse order?
• Create the same pattern using a while loop?
• Start every row from a different number?
• Replace the numbers with alphabets?

Drop your solution below! 👇

23 Days. 23 Patterns. Stronger Python Logic. 🐍🔥

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