Python Coding Challenge - Question with Answer (ID 310826)

 

Explanation:

1. Assign Value to a

a = 0

a stores 0.

0 is Falsy in Python.

2. Assign Value to b

b = 7

b stores 7.

7 is Truthy.

3. Assign Value to c

c = 3

c stores 3.

3 is Truthy.

4. Evaluate the Expression

print(a or b and c)

Python evaluates and before or.

So the expression becomes:

print(a or (b and c))

5. Evaluate b and c

7 and 3

Both values are truthy, so and returns the last value:

3

6. Evaluate a or 3

0 or 3

Since 0 is falsy, or returns the other value:

3

7. Final Output

3

8. Important Rule

and → higher precedence

or  → lower precedence

Therefore:

a or b and c

is evaluated as:

a or (b and c)

Answer: 3

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