Python Coding Challenge - Question with Answer (ID 200826)

 

Explanation:

1. Complete Code

print(dict(zip("ABC", range(3)))["B"])

2. range(3)

First, Python evaluates:

range(3)

This generates:

0, 1, 2

So we have:

"ABC"  →  A  B  C

range  →  0  1  2

3. zip("ABC", range(3))

zip() pairs the elements from both sequences:

zip("ABC", range(3))

creates pairs conceptually like:

('A', 0)

('B', 1)

('C', 2)

4. dict()

Now dict() converts those pairs into a dictionary:

dict(zip("ABC", range(3)))

The resulting dictionary is:

{'A': 0, 'B': 1, 'C': 2}

5. ["B"] — Dictionary Lookup

Now Python accesses the value associated with key "B":

{'A': 0, 'B': 1, 'C': 2}["B"]

The value of "B" is:

1

6. print()

Finally:

print(1)

displays the result.

✅ Final Output

1

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