Python Coding Challenge - Question with Answer (ID -300526)

 

Explanation:

🔹 Step 1: Create List

x = [1,2,3,4]

Initial list:

[1,2,3,4]

Index positions:

0 → 1

1 → 2

2 → 3

3 → 4

🔹 Step 2: Start Loop

for i in x:

Python starts iterating over the list.

Current list:

[1,2,3,4]

🔹 Step 3: First Iteration

i = 1

Check:

1 % 2

Result:

1

Which is truthy.

So:

x.remove(1)

List becomes:

[2,3,4]

🔹 Step 4: Loop Moves to Next Index

⚠️ Here comes the trap 😈

After removing 1, everything shifts left:

0 → 2

1 → 3

2 → 4

But the loop's internal index moves forward to the next position.

So Python now goes to:

index 1

Value at index 1:

3

👉 2 gets skipped completely!

🔹 Step 5: Second Iteration

i = 3

Check:

3 % 2

Result:

1

Truthy.

Execute:

x.remove(3)

List becomes:

[2,4]

🔹 Step 6: Loop Ends

Current list:

[2,4]

No more elements to iterate.

🔹 Step 7: Print Result

print(x)

Output:

[2,4]

Book: Python for Cybersecurity