Python Coding Challenge - Question with Answer (ID -150526)

 

Explanation:

🔹 Step 1: Understand Operator Priority

In Python:

and → evaluated before → or

So Python first evaluates:

0 and [1]

{} and 7

Expression becomes:

[] or 0 or {} or "X"

🔹 Step 2: Evaluate 0 and [1]

0 and [1]

👉 0 is falsy ❌

For and:

If first value is falsy → return it immediately

So:

0 and [1] → 0

🔹 Step 3: Evaluate {} and 7

{} and 7

👉 {} is empty dictionary

Empty dict = falsy ❌

For and:

Return first falsy value

So:

{} and 7 → {}

🔹 Step 4: Expression Now Becomes

[] or 0 or {} or "X"

Now Python evaluates or from left to right.

🔹 Step 5: Evaluate []

[]

👉 Empty list = falsy ❌

Move to next value

🔹 Step 6: Evaluate 0

0

👉 0 = falsy ❌

Move ahead

🔹 Step 7: Evaluate {}

{}

👉 Empty dictionary = falsy ❌

Move ahead

🔹 Step 8: Evaluate "X"

"X"

👉 Non-empty string = truthy ✅

For or:

Return FIRST truthy value

So result becomes:

"X"

🔹 Step 9: Final Print

print("X")

👉 Final Output:

X