Saturday, 23 May 2026

Python Coding Challenge - Question with Answer (ID -230526)

 


Explanation:

๐Ÿ”น Step 1: Create List
x = [3,2,1]

A list is created:

[3,2,1]

๐Ÿ”น Step 2: Create Special Iterator
it = iter(x.pop, 2)

⚠️ This is a VERY special form of iter() ๐Ÿ˜ˆ

Syntax:

iter(callable, sentinel)

๐Ÿ”น Step 3: Understand x.pop
x.pop

This is NOT calling function yet ❌

It is just giving function reference.

So iterator will repeatedly do:

x.pop()

again and again.

๐Ÿ”น Step 4: Understand Sentinel Value
2

This is sentinel value.

Iterator stops WHEN:

x.pop() == 2

๐Ÿ”น Step 5: Execute next(it)
next(it)

Iterator internally calls:

x.pop()

⚠️ pop() removes LAST element.

Current list:

[3,2,1]

So:

x.pop() → 1

List becomes:

[3,2]

๐Ÿ”น Step 6: Compare with Sentinel

Returned value:

1

Sentinel:

2

Since:

1 != 2

iterator continues normally.

So:

next(it) → 1

๐Ÿ”น Step 7: Print Result
print(1)

๐Ÿ‘‰ Final Output:

1

๐Ÿ”ฅ Final Output
1

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