Python Coding Challenge - Question with Answer (ID -250526)

 

Code Explanation:

🔹 Step 1: Create List

x = [1,2,3]

Initial list:

[1,2,3]

🔹 Step 2: Start Loop

for i in x:

Python starts iterating through list.

⚠️ Important:

Loop uses INDEX positions internally 😈

Initial indexes:

0 → 1

1 → 2

2 → 3

🔹 Step 3: First Iteration

Current element:

i = 1

Execute:

x.remove(i)

So:

x.remove(1)

List becomes:

[2,3]

🔹 Step 4: Loop Moves to Next Index

⚠️ Here comes the trap 😈

After removing 1,

elements shifted left:

0 → 2

1 → 3

BUT loop now moves to NEXT index:

index = 1

At index 1:

3

So Python SKIPS 2 😈

🔹 Step 5: Second Iteration

Current element:

i = 3

Execute:

x.remove(3)

List becomes:

[2]

🔹 Step 6: Loop Ends

No more indexes left.

Final list:

[2]

🔹 Step 7: Print Result

print(x)

👉 Final Output:

[2]

🔥 Final Output

[2]

Book: Python for Chemistry from Fundamentals to Real-World Applications