Python Coding Challenge - Question with Answer (ID -181225)

 

 What’s happening here?

• fun(a, b) expects two parameters:

  a 
  b

• In the function call:

  fun(1, a=2)

  • 1 is passed as a positional argument

  • a=2 is passed as a keyword argument

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❌ The Problem (Tricky Part)

Python assigns arguments in this order:

1. Positional arguments first

2. Keyword arguments second

So Python tries to assign:

• 1 → a

• a=2 → a again ❌

➡️ This means a gets two values, which is not allowed.

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 Result

TypeError: fun() got multiple values for argument 'a'

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✅ Correct Ways to Call the Function

✔ Option 1: Use all positional arguments

print(fun(1, 2))

✔ Option 2: Use all keyword arguments

print(fun(a=1, b=2))

✔ Option 3: Mix (positional first, keyword next — without duplication)

print(fun(1, b=2))

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 Key Rule to Remember (Exam Favorite )

❗ A parameter cannot receive multiple values
❗ Positional arguments must come before keyword arguments

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