Python Coding Challenge - Question with Answer (ID -251225)

 

Explanation:

1. List Initialization

a = [1, 2, 3, 4]

b = [10, 20, 30]

c = []

a is a list with 4 elements.

b is a list with 3 elements.

c is an empty list that will store the results.

2. Slicing the List a

a[1:]

This removes the first element of a.

a[1:] becomes:

[2, 3, 4]

3. Applying zip()

zip(a[1:], b)

zip pairs elements from both lists position-wise.

It stops at the shorter list (b has 3 elements).

So:

zip([2, 3, 4], [10, 20, 30])

→ (2,10), (3,20), (4,30)

4. Loop Execution

for x, y in zip(a[1:], b):

Each iteration assigns:

First iteration → x = 2, y = 10

Second iteration → x = 3, y = 20

Third iteration → x = 4, y = 30

5. Subtraction and Append

c.append(x - y)

Calculation in each iteration:

x y x - y c becomes

2 10 -8 [-8]

3 20 -17 [-8, -17]

4 30 -26 [-8, -17, -26]

6. Final Print

print(c)

Prints the final list:

[-8, -17, -26]

Final Output

[-8, -17, -26]

Probability and Statistics using Python