Thursday, 24 July 2025

Python Coding Challange - Question with Answer (01240725)

 


Explanation:

  1. Initialization:


    i = 5
    • A variable i is set to 5.

  2. Loop Condition:


    while i > 0:
    • The loop runs as long as i is greater than 0.

  3. Decrement i:

    i -= 1
    • In each iteration, i is reduced by 1 before any checks or printing.

  4. Check for break:

    python
    if i == 2:
    break
    • If i becomes 2, the loop immediately stops (breaks).

  5. Print i:

    • If i is not 2, it prints the current value of i.


๐Ÿ”„ Iteration Details:

Before Loopi = 5
Iteration 1i becomes 4 → i != 2 → print(4)
Iteration 2i becomes 3 → i != 2 → print(3)
Iteration 3i becomes 2 → i == 2 → breaks loop

Output:

4
3

Key Concept:

  • break immediately stops the loop when the condition is met.

  • i -= 1 happens before the if check and print().


400 Days Python Coding Challenges with Explanation

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