Sunday 24 March 2024

Python pattern challenge - Day 6

 

# Function to print swastika

def swastika(row,col):

for i in range(row):

for j in range(col): 

# checking if i < row/2

if(i < row // 2): 

# checking if j<col/2

if (j < col // 2): 

# print '*' if j=0

if (j == 0):

print("*", end = "")

# else print space

else:

print(" ", end = " ")

# check if j=col/2 

elif (j == col // 2):

print(" *", end = "")

else:

# if i=0 then first row will have '*'

if (i == 0):

print(" *", end = "")

elif (i == row // 2):

print("* ", end = "")

else: 

# middle column and last column will 

# have '*' after i > row/2

if (j == col // 2 or j == col - 1):

print("* ", end = "")

# last row

elif (i == row - 1): 

# last row will be have '*' if 

# j <= col/2 or if it is last column

if (j <= col // 2 or j == col - 1):

print("* ", end = "")

else:

print(" ", end = " ")

else:

print(" ", end = " ")

print()

# Driver code


# odd number of row and column

# to get perfect swastika

row = 7; col = 7


# Function calling

swastika(row, col)


#clcoding.com


*     * * * *
*     *
*     *
* * * * * * * 
      *     * 
      *     * 
* * * *     * 

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