Python pattern challenge - Day 5

 

def print_pattern():

    for i in range(5, 0, -1):

        for j in range(i, 0, -1):

            print(chr(64 + j), end="")

        print()

print_pattern()

Solution and Explanation: 

def print_pattern()::

This line defines a function named print_pattern().

for i in range(5, 0, -1)::

This outer loop iterates over the range from 5 down to 1. The third argument -1 in range() means that it decrements by 1 in each iteration.

for j in range(i, 0, -1)::

This inner loop iterates over the range from the current value of i down to 1. So, for each iteration of the outer loop, this inner loop prints characters in decreasing order.

print(chr(64 + j), end=""):

Inside the inner loop, chr(64 + j) converts the integer ASCII value 64 + j to the corresponding character. Since we're starting from 'E' (ASCII value 69) and decrementing, 64 + j gives the ASCII value of the characters 'A' to 'E'.

end="" parameter is used to prevent print() from adding a newline character after each print, so the characters are printed horizontally.

print():

This print() statement is outside the inner loop. It's used to move to the next line after each inner loop iteration, creating a new line for the next set of characters.

print_pattern():

This line outside the function definition calls the print_pattern() function, causing the pattern to be printed according to the code within the function.