Monday 25 March 2024

Python Coding challenge - Day 157 | What is the output of the following Python Code?

 

#Code:

explain def foo(x):
    return x + 1
result = map(foo, [1, 2, 3, 4])
print(list(result))

Solution and Explanations: 

This Python code demonstrates the use of the map() function. Let's break it down step by step:

def foo(x): - This line defines a function named foo that takes a single argument x.

return x + 1 - Inside the foo function, it simply returns the value of x incremented by 1.

result = map(foo, [1, 2, 3, 4]) - Here, the map() function is used. It takes two arguments: a function (foo in this case) and an iterable ([1, 2, 3, 4] in this case). What map() does is it applies the function (foo) to each item in the iterable ([1, 2, 3, 4]), producing a new iterable containing the results. So, map(foo, [1, 2, 3, 4]) will apply foo to each element of the list [1, 2, 3, 4], resulting in [2, 3, 4, 5].

print(list(result)) - The map() function returns an iterator, so we need to convert it into a list to see the results. This line converts the result iterator into a list and prints it. The output will be [2, 3, 4, 5], which are the values obtained by applying the foo function to each element in the list [1, 2, 3, 4], incrementing each by 1.

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