Saturday 18 November 2023

Rewrite the following program using for loop. lst = ['desert', 'dessert', 'to', 'too', 'lose', 'loose'] s = 'Mumbai' i = 0 while i < len(lst) : if i > 3 : break else : print(i, lst[i], s[i]) i += 1

 Rewrite the following program using for loop.

lst = ['desert', 'dessert', 'to', 'too', 'lose', 'loose']

s = 'Mumbai'

i = 0

while i < len(lst) :

if i > 3 :

break

else :

print(i, lst[i], s[i])

i += 1


Here's the equivalent program using a for loop:

lst = ['desert', 'dessert', 'to', 'too', 'lose', 'loose']

s = 'Mumbai'

for i in range(len(lst)):

    if i > 3:

        break

    else:

        print(i, lst[i], s[i])

In this version, the for loop iterates over the indices of the lst list using range(len(lst)). The if condition inside the loop checks whether i is greater than 3, and if so, it breaks out of the loop. Otherwise, it prints the values of i, lst[i], and s[i]. The loop increment is handled automatically by the for loop construct, eliminating the need for an explicit increment (i += 1).






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