Saturday 25 November 2023

Python Coding challenge - Day 77 | What is the output of the following Python code?

 

Code : 


def fun(a, *args, s='!'):
    print(a, s)
    for i in args:
        print(i, s)

fun(10)

Solution and Explanation: 

Function Definition:

def fun(a, *args, s='!'):

The function fun is defined to take at least one argument a, followed by any number of additional positional arguments (*args), and an optional keyword argument s with a default value of '!'.


Print the First Argument and Suffix:

print(a, s)

This line prints the value of the first argument a followed by the value of the keyword argument s.


Loop through Additional Arguments:

for i in args:

    print(i, s)

This loop iterates through any additional positional arguments provided (if any) and prints each one followed by the value of the keyword argument s.


Function Call:

fun(10)

The function is called with the argument 10. Since no additional positional arguments are provided, only the first print statement is executed.


When you run this code, it will output:

10 !

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