Code Explanation:
Final Output:
[0, 1]
Python Developer June 10, 2025 Python Coding Challenge No comments
Final Output:
[0, 1]
Python Developer June 10, 2025 Python Coding Challenge No comments
Python Coding June 09, 2025 Python Quiz No comments
Global Scope:
Variable x = 10 is defined outside the function, so it's in the global scope.
Inside func():
print(x)x = 5
Here, you're trying to print x before assigning x = 5.
In Python, any assignment to a variable inside a function makes it a local variable, unless it's explicitly declared global or nonlocal.
So Python treats x as a local variable in func() throughout the function body, even before the line x = 5 is executed.
Error:
When print(x) runs, Python is trying to access the local variable x before it has been assigned. This leads to:
If you want to access the global x, you can do:
def func(): global x
print(x)
x = 5
x = 10func()Or simply remove the assignment if not needed.
If a variable is assigned anywhere in the function, Python treats it as local throughout that function—unless declared with global or nonlocal.
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Python Developer June 08, 2025 Data Science, Python No comments
Python Coding June 08, 2025 Python Quiz No comments
Index: 0 1 2 3 4Value: [1, 2, 3, 4, 5]This is list slicing using the format:
[start : stop : step]
Start = 1 → Start at index 1 (2)
Stop = 4 → Stop before index 4 (so last included is index 3)
Step = 2 → Take every 2nd element
Start at index 1 → value is 2
Next step: skip 1 and move to index 3 → value is 4
Index 5 would be next, but stop is at 4 → stop slicing
[2, 4]
Python Developer June 08, 2025 Python Coding Challenge No comments
Python Developer June 08, 2025 Python Coding Challenge No comments
Python Coding June 08, 2025 Python Quiz No comments
lst = [0, 1, 2, 3, 4]# Indexes: 0 1 2 3 4
You're slicing from index 1 (inclusive) to index 4 (exclusive), so you're selecting:
[1, 2, 3]
You're replacing the selected slice [1, 2, 3] with the new values [7, 8].
The original list had 3 elements in the slice.
The new list has 2 elements.
Python allows list slices to be replaced by shorter or longer sequences, and it automatically adjusts the size of the original list.
lst = [0, 7, 8, 4]
0 is unchanged.
[1, 2, 3] is replaced by [7, 8].
4 stays at the end.
[0, 7, 8, 4]Python Developer June 08, 2025 Python Coding Challenge No comments
Python Developer June 08, 2025 Python Coding Challenge No comments
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Python Coding June 06, 2025 Python Quiz No comments
This assigns the string "banana" to the variable s.
This uses the .count() method, which counts how many times a specific character or substring appears in the string s.
In this case, it looks for how many times the lowercase letter 'a' appears in "banana".
The string "banana" contains the letter 'a' at:
Index 1
Index 3
Index 5
So there are 3 occurrences.
It prints the result of s.count('a'), which is 3.
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Python Developer June 06, 2025 Python Coding Challenge No comments
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a[start:stop:step]
start → where to begin (inclusive)
stop → where to stop (exclusive)
step → direction and spacing
If positive, slicing moves left to right
If negative, slicing moves right to left
a = [1, 2, 3, 4, 5, 6, 7]print(a[1:6:-1])start = 1 → this is the element 2 (a[1])
stop = 6 → this is the element 7 (a[6])
step = -1 → go backwards
When step is negative, it slices backward. So Python expects:
start > stop
But here:
1 < 6 → invalid direction for -1 step
[]
No elements are returned because the step is -1, but the direction (from index 1 to 6) is invalid for backward slicing.
a[1:6:-1] → [] # Because step = -1 (backward), but start < stop, so nothing is selected.
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Python Developer June 05, 2025 Python Coding Challenge No comments
Python Developer June 05, 2025 Python Coding Challenge No comments
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