Thursday, 27 August 2026

Python Coding Challenge - Question with Answer (ID 270826)

 


Explanation:

๐Ÿ’ป Code
x = [] or [1] or [2]
print(x)

๐Ÿ”น Line 1: x = [] or [1] or [2]
x = [] or [1] or [2]

Python evaluates the values from left to right.

๐Ÿ”น Step 1: []
[]

[] is an empty list, so Python considers it Falsy.

Therefore, Python moves to the next value.

๐Ÿ”น Step 2: [1]
[1]

[1] is a non-empty list, so it is Truthy.

Python stops here because or has already found a Truthy value.

๐Ÿ”น Step 3: [2]
[2]

This value is never evaluated as the result, because Python already found [1].

๐Ÿ”น Line 2: print(x)
print(x)

x contains the first Truthy value, which is [1].

๐ŸŽฏ Output
[1]

Book: 100 Python Automation Projects for Smart Developers

0 Comments:

Post a Comment

Popular Posts

Categories

100 Python Programs for Beginner (119) AI (340) Android (25) AngularJS (1) Api (7) Assembly Language (2) aws (31) Azure (12) BI (10) book (1) Books (345) Bootcamp (14) C (78) C# (12) C++ (83) cloud (1) Course (89) Coursera (302) Cybersecurity (36) data (10) Data Analysis (46) Data Analytics (31) data management (16) Data Science (422) Data Strucures (18) Deep Learning (217) Django (16) Downloads (3) edx (21) Engineering (15) Euron (30) Events (7) Excel (24) Finance (13) flask (4) flutter (1) FPL (17) Generative AI (77) Git (13) Google (54) Hadoop (3) HTML Quiz (1) HTML&CSS (48) IBM (43) IoT (3) IS (25) Java (99) Leet Code (4) Machine Learning (393) Meta (24) MICHIGAN (5) microsoft (13) Nvidia (8) Pandas (16) PHP (20) Projects (34) Python (1362) Python Coding Challenge (1225) Python Library (1) Python Mathematics (13) Python Mistakes (51) Python Quiz (612) Python Tips (102) Questions (3) R (72) React (7) Scripting (3) security (4) Selenium Webdriver (4) Software (21) SQL (55) Udemy (20) UX Research (1) web application (11) Web development (9) web scraping (3)

Followers

Python Coding for Kids ( Free Demo for Everyone)