Tuesday, 7 July 2026

Python Coding Challenge - Question with Answer (ID -070726)

 


Explanation:

Line 1: Create a List
a = [1, 2]

Explanation:

A list named a is created.
It contains two elements: 1 and 2.

Memory:

a ──► [1, 2]

Line 2: Copy the List
b = a.copy()

Explanation:

copy() creates a new list with the same elements as a.
Now a and b are different lists stored in different memory locations.

Memory:

a ──► [1, 2]

b ──► [1, 2]

Important: Changes made to b will not affect a.

Line 3: Add an Element
b.append(3)

Explanation:

append(3) adds the value 3 to the end of list b.

Now:

a ──► [1, 2]

b ──► [1, 2, 3]

Only b changes because it is a separate copy.

Line 4: Print the Original List
print(a)

Explanation:

This prints the original list a.
Since a was never modified, it still contains only 1 and 2.

Output:

[1, 2]
Final Memory Diagram

Before append():

a ──► [1, 2]
b ──► [1, 2]

After append():

a ──► [1, 2]

b ──► [1, 2, 3]
Why doesn't a change?

Because:

a.copy() creates a new independent list.
b.append(3) modifies only the new list b.
The original list a remains unchanged.

Final Output
[1, 2]

Book: PYTHON LOOPS MASTERY

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