Monday, 28 April 2025

Python Coding Challange - Question with Answer (01290425)

 


Step 1: Define the list

letters = ["a", "b", "c", "d"]

This creates a list with 4 elements:

  • Index 0 → "a"

  • Index 1 → "b"

  • Index 2 → "c"

  • Index 3 → "d"


Step 2: The loop

for i in range(2):

This means i will take on the values 0 and 1.


Step 3: Accessing list elements

letters[i*2]
  • When i = 0:
    i*2 = 0, so letters[0] → "a"
    → prints a

  • When i = 1:
    i*2 = 2, so letters[2] → "c"
    → prints c


✅ Final Output:


a
c

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