Tuesday 21 May 2024

Python Coding challenge - Day 211 | What is the output of the following Python Code?

 

Code:

explain c = '13\t14' 

print(c.index('\t'))

Solution and Explanation:

Let's break down the code c = '13\t14' and print(c.index('\t')) to understand what it does:

c = '13\t14'

Here, we are assigning a string to the variable c.

The string '13\t14' contains the characters 1, 3, a tab character (\t), 1, and 4.

The \t is an escape sequence that represents a tab character.

print(c.index('\t'))

The index method is called on the string c.

c.index('\t') searches the string c for the first occurrence of the tab character (\t).

The index method returns the index (position) of the first occurrence of the specified value.

If the specified value is not found, it raises a ValueError.

Let's put it all together:

The string c is '13\t14'. Visually, it can be represented as:

13<TAB>14

where <TAB> is a single tab character.

When we call c.index('\t'), we are looking for the index of the tab character in the string c.

In the string '13\t14', the tab character is located at index 2 (considering zero-based indexing):

'1' is at index 0

'3' is at index 1

'\t' (tab) is at index 2

'1' is at index 3

'4' is at index 4

Therefore, the statement print(c.index('\t')) will output 2 because the tab character is found at index 2 in the string c.


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