Saturday 11 May 2024

Python Coding challenge - Day 202 | What is the output of the following Python Code?

 

Code:

x = [1, 2, 3, 4, 5]
a, *_, b = x
print(a, b)

Solution and Explanation:

Let's break down the Python code step by step:

x = [1, 2, 3, 4, 5]
a, *_, b = x
print(a, b)
List Assignment: x = [1, 2, 3, 4, 5]

This line initializes a list named x with five elements: [1, 2, 3, 4, 5].
Extended Unpacking: a, *_, b = x

This line uses extended unpacking to assign values from the list x to variables a and b, while ignoring the rest of the elements.
The * (asterisk) operator is used to capture multiple values into a list. In this case, * is followed by an underscore (_), which is a common convention in Python to indicate that the variable is a placeholder and its value is not used.
The first element of x is assigned to a, and the last element is assigned to b, while all other elements are captured by the _ variable (which is ignored).
Print Statement: print(a, b)

This line prints the values of variables a and b separated by a space.
So, what does this code output?

a will be assigned the value 1, which is the first element of the list x.
b will be assigned the value 5, which is the last element of the list x.
The other elements of the list x are captured by the _ variable, but since they are not used in the print statement, they are ignored.
Therefore, the output of the code will be:
1 5


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