# Python Coding challenge - Day 201 | What is the output of the following Python Code?

### Code:

class Powerizer(int):

def __pow__(self, other):

return super().__pow__(other ** 2)

p = Powerizer(2)

result = p ** 3

print(result)

### Solution and Explanation:

let's break down the code:

Class Definition:

class Powerizer(int):
def __pow__(self, other):
return super().__pow__(other ** 2)
Powerizer(int): This line defines a class named Powerizer that inherits from the int class. Instances of Powerizer will inherit all properties and methods of integers.
def __pow__(self, other): This method overrides the power behavior (__pow__) for instances of the Powerizer class. It's invoked when the ** operator is used with instances of Powerizer.
return super().__pow__(other ** 2): Inside the __pow__ method, it squares the other operand and then calls the __pow__ method of the superclass (which is int). It passes the squared other operand to the superclass method. Essentially, it calculates the power of the Powerizer instance with the squared value of other.
Object Instantiation:

p = Powerizer(2)
This line creates an instance of the Powerizer class with the value 2.
Power Operation:

result = p ** 3
This line performs a power operation using the ** operator. Since p is an instance of Powerizer, the overridden __pow__ method is invoked. The value 3 is passed as other. Inside the overridden __pow__ method, 3 is squared to 9. Then, the superclass method (int.__pow__) is called with the squared other value. Essentially, it calculates p raised to the power of 9.

print(result)
This line prints the value of result, which is the result of the power operation performed in the previous step.
So, the output of this code will be 512, which is the result of 2 raised to the power of 9 (2^9).