Sunday 19 May 2024

Python Coding challenge - Day 209 | What is the output of the following Python Code?

 

Code:

h = [5, 6, 7, 8]

h.pop()

h.pop(0)

print(h)

Solution and Explanation: 

Let's break down the given Python code and explain what each line does:

h = [5, 6, 7, 8]

This line creates a list h with the elements 5, 6, 7, and 8.

h = [5, 6, 7, 8]
h.pop()

The pop() method removes and returns the last item from the list. Since no argument is provided, it removes the last element, which is 8.

Before h.pop():

h = [5, 6, 7, 8]
After h.pop():

h = [5, 6, 7]
h.pop(0)

The pop(0) method removes and returns the item at index 0 from the list. This means it removes the first element, which is 5.

Before h.pop(0):

h = [5, 6, 7]
After h.pop(0):

h = [6, 7]
print(h)

This line prints the current state of the list h to the console.

print(h)
The output will be:

[6, 7]
Summary
Initially, the list h is [5, 6, 7, 8].
The first h.pop() removes the last element, resulting in [5, 6, 7].
The second h.pop(0) removes the first element, resulting in [6, 7].
Finally, print(h) outputs [6, 7].
So the final state of the list h after these operations is [6, 7].

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