Python Coding challenge - Day 1113| What is the output of the following Python Code?

 

Code Explanation:

🔹 1. Importing the module

import threading

This line imports the threading module.

It allows you to create and manage threads (multiple flows of execution running in parallel).

🔹 2. Initializing a variable

x = 0

A global variable x is created.

It is initialized with value 0.

This variable will be accessed and modified by the thread.

🔹 3. Defining the task function

def task():

A function named task is defined.

This function will be executed inside a separate thread.

🔹 4. Declaring global variable inside function

global x

This tells Python that x refers to the global variable, not a local one.

Without this, Python would create a local x inside the function.

🔹 5. Modifying the variable

x = x + 1

The value of x is increased by 1.

Since x is global, the change affects the original variable.

🔹 6. Creating a thread

t = threading.Thread(target=task)

A new thread t is created.

The target=task means this thread will run the task() function.

🔹 7. Starting the thread

t.start()

This starts the thread execution.

The task() function begins running concurrently.

🔹 8. Waiting for thread to finish

t.join()

This makes the main program wait until the thread finishes execution.

Ensures that task() completes before moving forward.

🔹 9. Printing the result

print(x)

After the thread finishes, the updated value of x is printed.

Output will be:

1

Book:  500 Days Python Coding Challenges with Explanation