Thursday, 5 March 2026

Python Coding challenge - Day 1062| What is the output of the following Python Code?

 


Code Explanation:

๐Ÿ”น 1️⃣ Defining Base Class A

class A:
    def f(self): return "A"

Base class A

Method f() returns "A"

๐Ÿ”น 2️⃣ Defining Class B (Inherits from A)
class B(A):
    def f(self): return super().f() + "B"

B overrides method f

Calls super().f() first

Then appends "B"

So:

B.f() → A.f() + "B"

๐Ÿ”น 3️⃣ Defining Class C (Also Inherits from A)
class C(A):
    def f(self): return super().f() + "C"

Same structure as B

Calls super().f()

Appends "C"

So:

C.f() → A.f() + "C"

๐Ÿ”น 4️⃣ Defining Class D (Multiple Inheritance)
class D(B, C):
    def f(self): return super().f() + "D"

D inherits from B and C

Overrides f

Calls super().f()

Appends "D"

๐Ÿ”ฅ The Most Important Part: MRO

Let’s check the Method Resolution Order.

D.mro()

Result:

[D, B, C, A, object]

๐Ÿ“Œ Python will search methods in this order.

๐Ÿง  Step-by-Step Execution of D().f()
print(D().f())
๐Ÿ”น Step 1: Call D.f()

Inside D.f():

return super().f() + "D"

Now we go to the next class in MRO after D, which is:

B
๐Ÿ”น Step 2: Execute B.f()

Inside B.f():

return super().f() + "B"

Next class in MRO after B is:

C
๐Ÿ”น Step 3: Execute C.f()

Inside C.f():

return super().f() + "C"

Next class in MRO after C is:

A
๐Ÿ”น Step 4: Execute A.f()

Inside A.f():

return "A"

Returns:

"A"
๐Ÿงฉ Now We Build Backwards

From A.f() → returns "A"

Then:

C adds:
"A" + "C" → "AC"
B adds:
"AC" + "B" → "ACB"
D adds:
"ACB" + "D" → "ACBD"



✅ Final Correct Output
ACBD

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