Python Coding Challenge - Question with Answer (ID -110226)

 

Explanation:

🔹 1️⃣ Initial Tuple Creation

t = (10, 20, 30)

A tuple with 3 elements is created.

Index positions:

Index Value

0 10

1 20

2 30

🔹 2️⃣ Loop Setup

for i in range(len(t)):

len(t) = 3

range(3) → generates: 0, 1, 2

Important: range(len(t)) is calculated once at the beginning.

Even if t changes inside the loop, the loop still runs 3 times only.

Iteration-by-Iteration Execution

🔹 🔁 Iteration 1 (i = 0)

Current tuple:

(10, 20, 30)

Expression:

t = t[:0] + (t[0] + 0,) + t[1:]

Breaking it down:

t[:0] → () (empty tuple)

t[0] + 0 → 10 + 0 = 10

(10,) → single-element tuple

t[1:] → (20, 30)

New tuple:

() + (10,) + (20, 30)

= (10, 20, 30)

🔹 🔁 Iteration 2 (i = 1)

Current tuple:

(10, 20, 30)

Expression:

t = t[:1] + (t[1] + 1,) + t[2:]

Breaking it down:

t[:1] → (10,)

t[1] + 1 → 20 + 1 = 21

(21,)

t[2:] → (30,)

New tuple:

(10,) + (21,) + (30,)

= (10, 21, 30)

🔹 🔁 Iteration 3 (i = 2)

Current tuple:

(10, 21, 30)

⚠ Notice index 1 is already modified to 21.

Expression:

t = t[:2] + (t[2] + 2,) + t[3:]

Breaking it down:

t[:2] → (10, 21)

t[2] + 2 → 30 + 2 = 32

(32,)

t[3:] → () (empty)

New tuple:

(10, 21) + (32,) + ()

= (10, 21, 32)

🏁 Final Output

print(t)

✅ Output:

(10, 21, 32)

Mastering Task Scheduling & Workflow Automation with Python