Tuesday 11 June 2024

Python Coding challenge - Day 226 | What is the output of the following Python Code?

 

Code:

x = "123"

y = int(x)

z = str(y)

print(x is z)

Solution and Explanation:

Let's break down the code step by step to understand what's happening and why print(x is z) will produce a specific result.

Assignment: x = "123"

Here, x is assigned the string value "123".

Conversion to Integer: y = int(x)

This line converts the string x to an integer. So, y becomes the integer 123.

Conversion back to String: z = str(y)

This line converts the integer y back to a string. So, z becomes the string "123".

Identity Check: print(x is z)

The is operator checks if x and z refer to the same object in memory.

Even though x and z both contain the string "123", they are two distinct objects. In Python, is checks for object identity, not equality. This means it checks whether both variables point to the exact same object in memory.

Here's a more detailed look:

After x = "123", x points to a string object "123" in memory.

After y = int(x), y points to an integer object 123 in memory.

After z = str(y), z points to a new string object "123" in memory. This new string object has the same value as x but is a different object.

Therefore, when you execute print(x is z), it will print False because x and z are not the same object in memory.

Therefore, when you execute print(x is z), it will print False because x and z are not the same object in memory.

To summarize:

x == z would be True because the contents of the strings are the same.

x is z is False because x and z are different objects in memory.

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