Sunday 2 June 2024

Python Coding challenge - Day 223 | What is the output of the following Python Code?

 

Let's break down the code and explain what it does:

my_num1 = -2 my_num2 = -3 print(my_num1 % my_num2)

Variable Assignment:

  • my_num1 = -2: This assigns the value -2 to the variable my_num1.
  • my_num2 = -3: This assigns the value -3 to the variable my_num2.

Modulus Operation:

  • The modulus operator % returns the remainder of the division of one number by another.
  • my_num1 % my_num2 computes the remainder when -2 is divided by -3.
  1. Calculation:

    • To understand the result of -2 % -3, we need to know how the modulus operation works with negative numbers.

    • The formula for the modulus operation is:

      π‘Ž%𝑏=π‘Ž(𝑏×int(π‘Ž/𝑏))

      where int(a / b) represents the integer division (floor division) of a by b.

    • Applying this to our numbers:

      2%3=2(3×int(2/3))
    • First, calculate the integer division:

      int(2/3)=int(0.666...)=0

      (since -2 / -3 is approximately 0.666, and taking the floor gives us 0).

    • Now, plug this back into the formula:

      2%3=2(3×0)=20=2
  2. Result:

    • Therefore, my_num1 % my_num2 results in -2.

Output:

  • print(my_num1 % my_num2) will print -2.

So, the final output of the code will be: -2

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