Saturday 6 April 2024

Python Coding challenge - Day 167 | What is the output of the following Python Code?

 

Code:

my_dict = {'a': 1, 'b': 2, 'c': 3}

value = my_dict.pop('d', 0)

print(value)

Solution and Explanation:

Let's break down the code step by step:

my_dict = {'a': 1, 'b': 2, 'c': 3}: This line initializes a dictionary named my_dict with three key-value pairs. The keys are 'a', 'b', and 'c', and their corresponding values are 1, 2, and 3 respectively.

value = my_dict.pop('d', 0): The pop() method in Python is used to remove and return the value associated with a specified key. In this line, 'd' is the key being looked up in the dictionary. However, since 'd' is not a key in my_dict, the default value 0 is returned instead of raising a KeyError.

If the key 'd' exists in the dictionary, its corresponding value would be returned and removed from the dictionary.

If the key 'd' does not exist in the dictionary, the second argument of pop() (which is 0 in this case) is returned without modifying the dictionary.

Therefore, value will be assigned the value returned by pop(), which is 0.

print(value): This line prints the value stored in the variable value. Since value holds 0 (the default value returned by pop()), the output of this line will be 0.

So, the output of the code will be:

0

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