Friday 26 April 2024

10 tricky python quiz with answers



  • What will be the output of the following code snippet?

print(bool(""))

Answer: False

Explanation: An empty string is considered to be False in a boolean context.


  • What will be the output of the following code snippet?

print(1 + "2")

Answer: TypeError: unsupported operand type(s) for +: 'int' and 'str'

Explanation: You cannot add an integer and a string in Python.


  • What will be the output of the following code snippet?

print(2 * "2")

Answer: '22'

Explanation: In Python, you can multiply a string by an integer, which will result in the string being repeated that many times.


  • What will be the output of the following code snippet?

print(0 == False)

Answer: True

Explanation: In Python, both 0 and False are considered to be False in a boolean context.


  • What will be the output of the following code snippet?

print(len("Hello, World!"))

Answer: 13

Explanation: The len() function returns the length of a string, which is the number of characters it contains.


  • What will be the output of the following code snippet?

print(1 in [1, 2, 3])

Answer: True

Explanation: The in keyword can be used to check if a value is present in a list.


  • What will be the output of the following code snippet?

print({1, 2, 3} & {2, 3, 4})

Answer: {2, 3}

Explanation: The & operator can be used to find the intersection of two sets.


  • What will be the output of the following code snippet?

print(1 > 2 > 3)

Answer: False

Explanation: In Python, the > operator has a higher precedence than the and operator, so the expression is evaluated as (1 > 2) and (2 > 3), which is False.


  • What will be the output of the following code snippet?

print(1 is 1.0)

Answer: False

Explanation: In Python, the is keyword checks if two variables refer to the same object, not if they have the same value.


  • What will be the output of the following code snippet?

print(1 is not 1.0)

Answer: True

Explanation: The is not keyword checks if two variables do not refer to the same object.

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