Python Coding Challenge - Question with Answer (ID 280726)

 

Explanation:

✅ Line 1: Create a List

a = [1, 2]

Explanation

A new list object is created in memory.

Variable a stores the reference (address) of that list.

Memory

a ─────► [1, 2]

✅ Line 2: Assign Another Variable

b = a

Explanation

No new list is created.

b simply points to the same list as a.

Memory

a ──┐

    ├────► [1, 2]

b ──┘

Both variables refer to the same object.

✅ Line 3: Create a New List Using +

a = a + [3]

Explanation

This line is not modifying the existing list.

Instead,

Python creates a new list by combining:

[1, 2] + [3]

Result:

[1, 2, 3]

Variable a is updated to point to this new list.

The original list remains unchanged.

Memory Before

a ──┐

    ├────► [1, 2]

b ──┘

Memory After

a ─────► [1, 2, 3]

b ─────► [1, 2]

Notice that b is still pointing to the original list.

✅ Line 4: Print

print(b)

Explanation

b still references the original list.

So Python prints:

[1, 2]

✅ Final Output

[1, 2]

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