Python Coding Challenge - Question with Answer (ID -020426)

 

Code Explanation:

🔹 1. Creating the List

lst = [1,2,2,3,3,3]

👉 A list is created containing numbers.

👉 Some numbers are repeated:

1 → 1 time

2 → 2 times

3 → 3 times

🔹 2. Creating an Empty Dictionary

freq = {}

👉 An empty dictionary is created.

👉 This will store:

key = number

value = count (frequency)

🔹 3. Loop Through Each Element

for x in lst:

👉 The loop runs through each item in the list one by one:

First 1, then 2, 2, 3, 3, 3

🔹 4. Counting Logic (Main Step)

freq[x] = freq.get(x,0) + 1

👉 This is the most important line:

freq.get(x, 0) → gets current count of x

If x is not present → returns 0

Then +1 increases the count

Step-by-step:

First 1 → {1:1}

First 2 → {1:1, 2:1}

Second 2 → {1:1, 2:2}

First 3 → {1:1, 2:2, 3:1}

Second 3 → {1:1, 2:2, 3:2}

Third 3 → {1:1, 2:2, 3:3}

🔹 5. Printing the Result

print(freq)

👉 Displays the final dictionary

✅ Final Output:

{1: 1, 2: 2, 3: 3}