Monday, 2 November 2026

Python Coding challenge - Day 1301| What is the output of the following Python Code?

 

Code Explanation:

1. Defining the Outer Function

def multiplier(n):

- Defines a function named multiplier.
- It accepts one parameter n.
- This function will create another function that remembers the value of n.
- This is the foundation of a Closure in Python.

2. Defining the Inner Function
    def calculate(x):
- Defines an inner function named calculate.
- It accepts one parameter x.
- Since this function is defined inside multiplier(), it can access variables from the outer function.

3. Returning the Calculation
        return x * n
- Multiplies x by n.
- Here, x is a local parameter of calculate().
- n comes from the enclosing multiplier() function.
- Even after the outer function finishes executing, the inner function remembers the value of n.
Important: This ability to remember variables from an enclosing scope is called a closure.

4. Returning the Inner Function
    return calculate
- Returns the inner function itself, not its result.
- Notice that we use calculate, not calculate().
- This allows the returned function to be stored in another variable and called later.

5. Creating the Double Function
double = multiplier(2)
- Calls multiplier() with n = 2.
- The inner function calculate is returned.
- It remembers that n is 2.
- The returned function is stored in double.
So logically:

double(x) = x * 2

6. Creating the Triple Function
triple = multiplier(3)
- Calls multiplier() again, this time with n = 3.
- A new inner function is returned.
- This function remembers n = 3.
- It is stored in the variable triple.
So logically:
triple(x) = x * 3

7. Calling Both Functions
print(double(triple(4)))

Let's evaluate this expression step by step.

Step 1: Execute the innermost function:
triple(4)

Since triple remembers n = 3:

4 * 3 = 12

Step 2: Pass the result to double():
double(12)

Since double remembers n = 2:

12 * 2 = 24

Step 3: Print the final result:
print(24)


Final Output
24

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