Python Coding challenge - Day 1122| What is the output of the following Python Code?

 

Code Explanation:

📌 1. Class A Definition

class A:

    def show(self, x=1):

        return x

✅ What happens:

A class A is created.

Method show():

Takes parameter x

Default value → 1

Returns x as it is

📌 2. Class B Definition (Inheritance)

class B(A):

✅ What happens:

B inherits from A

So B gets access to:

All methods of A

Including show()

📌 3. Method Overriding in B

def show(self, x=2):

    return super().show(x+1)

✅ Key Concepts:

🔹 1. Method Overriding

B defines its own show()

This overrides A.show()

🔹 2. Default Argument Change

In A: x = 1

In B: x = 2

👉 So calling obj.show() will use:

x = 2

🔹 3. Use of super()

super().show(x+1)

Calls parent class (A) method

Passes modified value: x + 1

📌 4. Object Creation

obj = B()

✅ What happens:

Object obj of class B is created

It will use B's methods first (due to method overriding)

📌 5. Function Call

print(obj.show())

📌 6. Step-by-Step Execution

🔹 Step 1: Call obj.show()

Since B overrides → B.show() is called

Default value:

x = 2

🔹 Step 2: Inside B.show()

return super().show(x+1)

👉 Compute:

x + 1 = 2 + 1 = 3

🔹 Step 3: Call Parent Method

A.show(3)

🔹 Step 4: Inside A.show()

return x

👉 Returns:

3

📌 7. Final Output

3

✅ Final Answer

3

Book:  500 Days Python Coding Challenges with Explanation