Python Coding challenge - Day 824| What is the output of the following Python Code?

 

Code Explanation:

1) Import the required modules

import json, math, operator

json lets you convert between Python objects and JSON text (dumps/loads).

math provides mathematical functions like sqrt.

operator gives function versions of operators (e.g. operator.add(a, b) ≡ a + b).

2) Create a Python dictionary

data = {"a": 9, "b": 16, "c": 4}

Defines a Python dict with three key/value pairs: "a": 9, "b": 16, "c": 4.

At this point data is a normal Python object (not JSON text).

3) Serialize the dictionary to a JSON string

txt = json.dumps(data)

json.dumps() converts the Python dict into a JSON-formatted string.

After this line txt is the string '{"a": 9, "b": 16, "c": 4}'.

Note: the numeric values remain numeric in JSON semantics but inside txt they are characters (part of a string).

4) Deserialize the JSON string back to a Python object

obj = json.loads(txt)

json.loads() parses the JSON text and returns the corresponding Python object.

obj becomes a Python dict with the same content as data: {"a": 9, "b": 16, "c": 4}.

5) Compute square roots and add them

val = operator.add(math.sqrt(obj["a"]), math.sqrt(obj["b"]))

obj["a"] → 9; math.sqrt(9) → 3.0.

obj["b"] → 16; math.sqrt(16) → 4.0.

operator.add(3.0, 4.0) returns 7.0.

So val = 7.0.

6) Add c, convert to int, and print

print(int(val + obj["c"]))

obj["c"] → 4.

val + obj["c"] → 7.0 + 4 = 11.0.

int(11.0) → 11 (drops any fractional part).

print(...) outputs the final result.

Final output

11

600 Days Python Coding Challenges with Explanation