Tuesday 6 February 2024

Python Coding challenge - Day 123 | What is the output of the following Python Code?

 


Code:

try:

    print("1")

except:

    print("2")

print("3")

Solution and Explanation:

The given code contains a try and except block, which are used for exception handling in Python. In this specific case, the try block contains a print("1") statement, and the except block contains a print("2") statement. Finally, there is a print("3") statement outside both blocks.

Here's how the code works:

The code attempts to execute the statements inside the try block.

If an exception occurs during the execution of the try block, the code jumps to the except block and executes the statements inside it.

If there is no exception in the try block, the except block is skipped.

In this case, since there are no statements in the try block that would raise an exception, the code will print "1" and then move on to the print("3") statement. Therefore, the output will be:


1 3

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