Sunday 4 February 2024

Python Coding challenge - Day 121 | What is the output of the following Python Code?

 

The provided code defines a function called calc that takes a variable number of arguments using the *args syntax. The function calculates the product of the number of arguments and the last argument in the given sequence. Let's break down the code:

def calc(*args):
    count = len(args)
    elem = args[count - 1]
    return count * elem

print(calc(2, 2, 1, 3))

Here's how the function works:

*args in the function definition allows the function to accept any number of arguments. All the arguments passed to the function are collected into a tuple named args.

count is assigned the length of the args tuple, which gives the number of arguments passed to the function.

elem is assigned the value of the last element in the args tuple (i.e., args[count - 1]).

The function returns the product of count and elem.

The print(calc(2, 2, 1, 3)) statement calls the calc function with the arguments 2, 2, 1, 3.

Now, let's substitute the values:

count is 4 (number of arguments).

elem is 3 (the last argument).

The function returns count * elem, which is 4 * 3 = 12.

Therefore, the final result printed by print(calc(2, 2, 1, 3)) is 12.






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