Tuesday 24 October 2023

Python Coding challenge - Day 49 | What is the output of the following Python code?

 


Question

k = [2, 1, 0, 3, 0, 2, 1]

print(k.count(k.index(0)))

Solution

The given list is k = [2, 1, 0, 3, 0, 2, 1].

k.index(0) finds the index of the first occurrence of the value 0 in the list k. In this case, the first occurrence of 0 is at index 2.

The result of k.index(0) is 2.

k.count(2) counts how many times the value 2 appears in the list k.

In the list k, the value 2 appears twice, at index 0 and index 5.

So, the final result is 2 because the index of the first occurrence of 0 (which is 2) appears twice in the list k.



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