# Python Coding challenge - Day 33 | What is the output of the following Python code?

def myfunc(a):

a = a + 2  # Step 1: Add 2 to the value of 'a' and store it back in 'a'

a = a * 2  # Step 2: Multiply the updated 'a' by 2 and store it back in 'a'

return a   # Step 3: Return the final value of 'a'

result = myfunc(2)  # Calling the 'myfunc' function with the argument 2

print(result)       # Printing the result

#### Here's a detailed explanation of each step:

def myfunc(a):: This line defines a function named myfunc that takes a single argument a.

a = a + 2: Inside the function, this line adds 2 to the value of a. In the context of the function call myfunc(2), a initially has a value of 2, so this line updates a to 4.

a = a * 2: Next, this line multiplies the updated value of a by 2. Since a was updated to 4 in the previous step, this line further updates a to 8.

return a: Finally, the function returns the value of a, which is now 8.

result = myfunc(2): Outside the function, we call myfunc(2) and store the result (which is 8) in a variable named result.

print(result): Finally, we print the value of result, which is 8, to the console.

So, when you run this code, it will output 8 because myfunc(2) performs a series of operations on the input value 2 and returns the result, which is 8.