Thursday, 2 May 2019

Finding a Year is leap or not in Python

@author python.learning
>>> def check_year(year):
...      if year%4==0 and year%100!=0 or year%400==0:
...            print ('leap year')
...      else:
               print ('not a leap year')
>>>  check_year(1972)
leap year
>>>  check_year(1975)
not a leap year



# or check with calendar
>>> import calendar
>>> print (calendar.isleap(1972) )
True
>>> print (calendar.isleap(1975) )
False

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