Saturday, 2 March 2019

Check Leap Year in Python

# Python program to check if the input year is a leap year or not
year = 2000
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
if (year % 4) == 0:

if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))

Output:

2000 is a leap year

0 Comments:

Post a comment

Popular Posts

Categories

Android (21) AngularJS (1) Assembly Language (2) Books (10) C (75) C# (4) C++ (81) Data Strucures (4) Downloads (1) Engineering (13) FPL (17) Hadoop (1) HTML&CSS (38) IS (25) Java (87) Leet Code (4) PHP (20) Python (214) R (69) Selenium Webdriver (2) Software (14) SQL (27)