Python Coding Challenge - Question with Answer (01191125)

 

Explanation:

lst = [1, 2, 3]

Creates a list lst containing three integers: 1, 2, 3.

This list will be used in the loops.

result = 0

Initializes a variable result to 0.

This variable will accumulate the count of times i == j is True.

for i in lst:

Starts the outer loop.

i will take each value in the list sequentially: 1, then 2, then 3.

for j in lst:

Starts the inner loop inside the outer loop.

For each value of i, j will iterate over the list [1, 2, 3].

result += (i == j)

(i == j) is a comparison: returns True if i equals j, else False.

In Python, True is treated as 1 and False as 0 when used in arithmetic.

Adds 1 to result if i == j, otherwise adds 0.

Step-by-step calculation:

i j i == j Added to result Cumulative result

1 1 True                 1                         1

1 2 False         0                         1

1 3 False         0                         1

2 1 False         0                         1

2 2 True                 1                         2

2 3 False         0                         2

3 1 False 0 2

3 2 False 0 2

3 3 True 1 3

Correction: Actually, let's carefully check:

Wait, outer loop iterates i=1,2,3 and inner loop j=1,2,3.

Count True values: (1==1),(2==2),(3==3) once for each combination?

Actually, let's compute carefully:

i=1: j=1 → True → +1 → result=1

i=1: j=2 → False → +0 → result=1

i=1: j=3 → False → +0 → result=1

i=2: j=1 → False → +0 → result=1

i=2: j=2 → True → +1 → result=2

i=2: j=3 → False → +0 → result=2

i=3: j=1 → False → +0 → result=2

i=3: j=2 → False → +0 → result=2

i=3: j=3 → True → +1 → result=3

Total result = 3

Ah! So in my previous message I mistakenly said 9. The correct answer is 3. Thanks for double-checking!

print(result)

Prints the final value of result.

Output:

3

Probability and Statistics using Python