Sunday, 16 November 2025

Python Coding Challenge - Question with Answer (01161125)

 Explanation:

List Initialization
a = [1, 4, 7, 10]

You create a list a that contains four numbers:
1, 4, 7, 10


Variable Initialization
s = 0

You create a variable s to store the sum.
Initially, sum = 0.

Loop Through Each Value
for v in a:

This loop will pick each value from list a, one by one.
So v becomes:
1 → 4 → 7 → 10

Check Condition
if v % 3 == 1:

You check if the number leaves remainder 1 when divided by 3.

Let’s check each:

v v % 3 Remainder Condition v%3==1?
1 1             Yes             ✔ Add
4 1             Yes             ✔ Add
7 1             Yes             ✔ Add
10 1             Yes             ✔ Add

All numbers satisfy the condition.

Add to Sum
s += v

Add all numbers that passed the condition.

s = 1 + 4 + 7 + 10 = 22

Print the Final Sum
print(s)

This prints:

22

Final Output: 22

Python Interview Preparation for Students & Professionals

0 Comments:

Post a Comment

Popular Posts

Categories

100 Python Programs for Beginner (118) AI (161) Android (25) AngularJS (1) Api (6) Assembly Language (2) aws (27) Azure (8) BI (10) Books (254) Bootcamp (1) C (78) C# (12) C++ (83) Course (84) Coursera (299) Cybersecurity (28) Data Analysis (24) Data Analytics (16) data management (15) Data Science (225) Data Strucures (14) Deep Learning (75) Django (16) Downloads (3) edx (21) Engineering (15) Euron (30) Events (7) Excel (17) Finance (9) flask (3) flutter (1) FPL (17) Generative AI (48) Git (6) Google (47) Hadoop (3) HTML Quiz (1) HTML&CSS (48) IBM (41) IoT (3) IS (25) Java (99) Leet Code (4) Machine Learning (197) Meta (24) MICHIGAN (5) microsoft (9) Nvidia (8) Pandas (12) PHP (20) Projects (32) Python (1219) Python Coding Challenge (898) Python Quiz (348) Python Tips (5) Questions (2) R (72) React (7) Scripting (3) security (4) Selenium Webdriver (4) Software (19) SQL (45) Udemy (17) UX Research (1) web application (11) Web development (7) web scraping (3)

Followers

Python Coding for Kids ( Free Demo for Everyone)