a = (10, '20', 30) print(min(a))

Code : 

a = (10, '20', 30)

print(min(a))

Solution and Explanation: 

The min() function compares the elements in the tuple lexicographically (in the case of strings) or numerically (in the case of numbers) and returns the smallest element. If the elements are of different types, it may raise a TypeError.

In your case, the tuple a contains elements of different types: an integer (10), a string ('20'), and another integer (30). The min() function will compare them based on their natural order. In this case, it will compare the integer 10, the string '20', and the integer 30.

The comparison is done lexicographically for strings, so '20' is considered smaller than both 10 and 30. Therefore, the output of the min(a) expression will be '20'.

If you run the provided code, the output will be:

20