Saturday 2 December 2023

Python Coding challenge - Day 83 | What is the output of the following Python Code?

 


Code : 

list1 = [1, 2, 4, 3]
list2 = [1, 2, 3, 4]
print(list1 != list2)


Solution and Explanation: 

The != operator in Python checks for inequality. In the given code, list1 and list2 are two lists with the same elements but in different orders. When you compare them using !=, the result is True because the order of elements matters in list comparison.


Here's a breakdown of the code:


list1 = [1, 2, 4, 3]

list2 = [1, 2, 3, 4]

print(list1 != list2)

list1 contains elements [1, 2, 4, 3].

list2 contains elements [1, 2, 3, 4].

When comparing list1 and list2 using !=, it checks if the two lists are not equal.

The order of elements is different, so the result of the comparison is True.

The print statement outputs True.

If the order of elements in both lists were the same, the result would be False.

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