Friday 1 December 2023

a = [] b = [a.append(i) for i in range(5)] print(a) print(b)

Code : 

a = []

b = [a.append(i) for i in range(5)]

print(a)

print(b)


Solution and Explanation: 

This code outputs the following:

[0, 1, 2, 3, 4]
[None, None, None, None, None]
List a is modified by the loop, and the loop overwrites the list b with None.

here is the explanation of the code:

The list comprehension [a.append(i) for i in range(5)] creates a list of None values. This is because the expression a.append(i) returns None, and the list comprehension only stores the return values of the expressions it contains.

The loop overwrites the list b with None because the list comprehension is evaluated before the loop. This means that the list b is already a list of None values by the time the loop starts.

The list a is modified by the loop because the expression a.append(i) appends the value i to the list a. This is because the expression a.append(i) is evaluated inside the loop, and the list a is modified in place.

Therefore, the output of the code is:

a: [0, 1, 2, 3, 4]
b: [None, None, None, None, None]

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