Python Coding Challenge - Question with Answer (01251125)

 

Explanation:

Initialize i

i = 0

The variable i is set to 0.

It will be used as the counter for the while loop.

Create an empty list

funcs = []

funcs is an empty list.

We will store lambda functions inside this list.

Start the while loop

while i < 5:

The loop runs as long as i is less than 5.

So the loop will execute for: i = 0, 1, 2, 3, 4.

Append a lambda that captures the current value of i

funcs.append(lambda i=i: i)

Why is i=i important?

i=i is a default argument.

Default arguments in Python are evaluated at the moment the function is created.

So each lambda stores the current value of i during that specific loop iteration.

What values get stored?

When i = 0 → lambda stores 0

When i = 1 → lambda stores 1

When i = 2 → lambda stores 2

When i = 3 → lambda stores 3

When i = 4 → lambda stores 4

So five different lambdas are created, each holding a different number.

Increment i

i += 1

After each iteration, i increases by 1.

This moves the loop to the next number.

Call all lambda functions and print their outputs

print([f() for f in funcs])

What happens here?

A list comprehension calls each stored lambda f() in funcs.

Each lambda returns the value it captured earlier.

Final Output:

[0, 1, 2, 3, 4]

Python for Civil Engineering: Concepts, Computation & Real-world Applications