Python Coding Challenge - Question with Answer (01241125)

 Explanation:

1. Function Definition

def f(n):

You define a function named f.

It expects one argument n.

2. First Condition – Check if n is even

    if n % 2 == 0:

n % 2 gives the remainder when n is divided by 2.

If the remainder is 0, then n is even.

For n = 6:

6 % 2 = 0, so this condition is TRUE.

3. First Return

        return n // 2

Because the first condition is true, the function immediately returns integer division of n by 2.

6 // 2 = 3

4. Second Condition (Skipped)

    if n % 3 == 0:

        return n // 3

These lines are never reached for n = 6.

Even though 6 is divisible by 3, the function already returned at the previous line.

5. Final Return (Also Skipped)

    return n

This would run only if neither condition was true.

But in this case, the function has already returned earlier.

6. Function Call

print(f(6))

Calls f(6)

As shown above, f(6) returns 3

So the program prints:

3

Final Output

3

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