Python Coding Challenge - Question with Answer (01181125)

 

Explanation:

1. Dictionary Creation

d = {'apple': 2, 'banana': 3, 'cherry': 4}

Creates a dictionary d with keys as fruit names and values as numbers.

Example content:

'apple': 2

'banana': 3

'cherry': 4

2. Initialize Counter

count = 0

Initializes a variable count to store the running total.

Starts at 0.

3. Loop Over Dictionary Items

for k, v in d.items():

Loops over each key-value pair in the dictionary.

k = key (fruit name), v = value (number).

.items() gives pairs: ('apple', 2), ('banana', 3), ('cherry', 4).

4. Check for Letter 'a' in Key

if 'a' in k:

Checks if the key contains the letter 'a'.

Only keys with 'a' are processed.

'apple' → True, 'banana' → True, 'cherry' → False.

5. Add Value to Counter

count += v

Adds the value v to count if the key has 'a'.

Step by step:

'apple': count = 0 + 2 → 2

'banana': count = 2 + 3 → 5

'cherry': skipped

6. Print Final Count

print(count)

Prints the final total of values where keys contain 'a'.

Output:

5

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